Question
  1. Complete the following chemical equations:
  1. $\text{Cr}_{2}\text{O}_{7}^{2-}\text{(aq)}+\text{H}_{2}\text{S}\text{(g)}+\text{H}^{+}\text{(aq)}\rightarrow$
  2. $\text{Cu}^{2+}\text{(aq)}+\text{I}^{-}\text{(aq)}\rightarrow$
  1. How would you account for the following:
  1. The oxidising power of oxoanions are in the order $VO^+_2 < Cr_2O^{2–}_7 –_4.$
  2. The third ionisation enthalpy of manganese (Z = 25) is exceptionally high.
  3. $Cr^{2+}$ is a stronger reducing agent than $Fe^{2+}.$

Answer

  1.  
  1. $\text{Cr}_{2}\text{O}_{7}^{2-}+\text{3H}_{2}\text{S}+\text{8H}^{+}\rightarrow\text{2Cr}^{3+}+\text{7H}_{2}\text{O}+\text{3S}$.
  2. $\text{2Cu}^{2+}+\text{4I}^{-}\rightarrow\text{Cu}_{2}\text{I}_{2}+\text{I}_{2}$.
  1.  
  1. It is due to increasing stability of lower species to which they are reduced.
  2. Because removing $3^{rd} e^-$ from extra stable $3d^5$ configuration is difficult in case of Mn.
  3. Because $d^3$ of $Cr^{2+} $is more stable than $d_5$ of $Fe^{3+}.$

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