Question
Complete the following table to draw the graph of $2x – 6y = 3$
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From given figure, in $\triangle M N K$, if $\angle M N K=90^{\circ}, \angle M=45^{\circ}, M K=6$, then for finding value of $M N$ and $K N$, complete the following activity.
Activity:
In $\triangle M N K, \angle M N K=90^{\circ}, \angle M=45^{\circ}$ [Given]
$\therefore \angle K=\square$
.....[Remaining angle of $\triangle M N K]$
By theorem of $45^{\circ}-45^{\circ}-90^{\circ}$ triangle,
$\therefore \square=\frac{1}{\sqrt{2}} MK$ and $\square=\frac{1}{\sqrt{2}} MK$
$\therefore MN =\frac{1}{\sqrt{2}} \times \square$ and $KN =\frac{1}{\sqrt{2}} \times 6$
$\therefore MN =3 \sqrt{2}$ and $KN =3 \sqrt{2}$
→→Activity:In $\triangle M N K, \angle M N K=90^{\circ}, \angle M=45^{\circ}$ [Given]
$\therefore \angle K=\square$
.....[Remaining angle of $\triangle M N K]$
By theorem of $45^{\circ}-45^{\circ}-90^{\circ}$ triangle,
$\therefore \square=\frac{1}{\sqrt{2}} MK$ and $\square=\frac{1}{\sqrt{2}} MK$
$\therefore MN =\frac{1}{\sqrt{2}} \times \square$ and $KN =\frac{1}{\sqrt{2}} \times 6$
$\therefore MN =3 \sqrt{2}$ and $KN =3 \sqrt{2}$
The faces of a die bear the numbers 1, 3, 5, 7, 9, 11. The die is rolled. Find the probability of getting a perfect square number on the upper face of the die.
From the given figure, in $\triangle A B C$, if $A D \perp B C, \angle C=45^{\circ}, A C=8 \sqrt{2}, B D=5$, then for finding value of $A D$ and $BC$, complete the following activity.
Activity: In $\triangle ADC$, if $\angle ADC =90^{\circ}, \angle C =45^{\circ}$ [Given]
$\therefore \angle DAC =\square \quad$..... [Remaining angle of $\triangle ADC ]$
By theorem of $45^{\circ}-45^{\circ}-90^{\circ}$ triangle,
$ \therefore \square=\frac{1}{\sqrt{2}} AC \text { and } \square=\frac{1}{\sqrt{2}} AC$
$\therefore AD =\frac{1}{\sqrt{2}} \times \square \text { and } DC =\frac{1}{\sqrt{2}} \times 8 \sqrt{2}$
$\therefore AD =8 \text { and } DC =8$
$\therefore BC = BD + DC$
$=5+8$
$=13 $
→Activity: In $\triangle ADC$, if $\angle ADC =90^{\circ}, \angle C =45^{\circ}$ [Given]
$\therefore \angle DAC =\square \quad$..... [Remaining angle of $\triangle ADC ]$
By theorem of $45^{\circ}-45^{\circ}-90^{\circ}$ triangle,
$ \therefore \square=\frac{1}{\sqrt{2}} AC \text { and } \square=\frac{1}{\sqrt{2}} AC$
$\therefore AD =\frac{1}{\sqrt{2}} \times \square \text { and } DC =\frac{1}{\sqrt{2}} \times 8 \sqrt{2}$
$\therefore AD =8 \text { and } DC =8$
$\therefore BC = BD + DC$
$=5+8$
$=13 $
Write the values of the following trigonometric ratios.
$\sin 30^{\circ}=\frac{1}{⬜}$
→$\sin 30^{\circ}=\frac{1}{⬜}$
Fill in the blanks with correct number
$\left|\begin{array}{ll}3 & 2 \\ 4 & 5\end{array}\right|=3 \times \square-\square \times 4=\square-8=\square$
→$\left|\begin{array}{ll}3 & 2 \\ 4 & 5\end{array}\right|=3 \times \square-\square \times 4=\square-8=\square$
Complete the following activity to find the number of natural numbers from 1 to 171 which are divisible by 5 .
.......... (I) theorem of angle bisector.
Complete the following activity to form a quadratic equation.
Activity :
Activity :