Question
Complete the reaction: $_{86}Rn^{220}\rightarrow _{84}Po^{216}+ .......$ :
✓
Answer
$_{86}Rn^{220 }\rightarrow _{84}Po^{216 }+ _ZX^A$
$Z + 84 = 86$ and $220 = 216 + A$
So $, Z = 2$ and $A = 4$
$2\alpha^4$
So, it is $\alpha$ particle.
$Z + 84 = 86$ and $220 = 216 + A$
So $, Z = 2$ and $A = 4$
$2\alpha^4$
So, it is $\alpha$ particle.
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