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Alternating Current — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsAlternating Current1 Mark
Question
In the circuit shown in fig., the resonant frequency is.
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Answer

  1. 225.08Hz
Explanation:
The resonant frequecy of a circuit is given by $\text{f}=\frac{1}{2\pi\sqrt{\text{LC}}}$
Given $\text{L}=0.1\text{H }\text{C}=5\mu\text{F }\text{R}=5\Omega$
Substituting them in formula for f gives
f = 225.08 Hz.

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