Question
Complete the reaction.
(i) $H _3 BO _3 \stackrel{373 K }{\longrightarrow} A + H _2 O$
(ii) $A \stackrel{413 K }{\longrightarrow} B + H _2 O$
(iii) $B \stackrel{\text { Red hot }}{\longrightarrow} C + H _2 O$

Answer

Boric acid when heated at 373 K gives metaboric acid (A) and A heated at 413 K it gives tetraboric acid (B). B heated at red hot it gives boric anhydride (C).
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