MCQ
Compound $'A'$ undergoes following sequence of reactions to give compound $'B'$ . The correct structure and chirality of compound $'B'$ is
[where $Et$ is $- C _{2} H _{5}$ ]
Compound $'A'$
- A

- B

- ✓

- D

[where $Et$ is $- C _{2} H _{5}$ ]
Compound $'A'$






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$(I) [FeF_6]^{-3}$
$(II) [V(H_2O)_6]^{+2}$
$(III) [Fe(H_2O)_6]^{+2}$
| List $I$ Complex | List $II$ Crystal Field splitting energy $\left(\Delta_0\right)$ |
| $A$ $\left[ Ti \left( H _2 O \right)_6\right]^{2+}$ | $I$ $-1.2$ |
| $B$ $\left[ V \left( H _2 O \right)_6\right]^{2+}$ | $II$ $-0.6$ |
| $C$ $\left[ Mn \left( H _2 O \right)_6\right]^{3+}$ | $III$ $0$ |
| $D$ $\left[ Fe \left( H _2 O \right)_6\right]^{3+}$ | $IV$ $-0.8$ |

