MCQ
The compound that will react most readily with $ NaOH $ to form methanol is
- ✓${(C{H_3})_4}{N^ + }{I^ - }$
- B$C{H_3}OC{H_3}$
- C${(C{H_3})_3}{S^ + }{I^ - }$
- D${(C{H_3})_3}Cl$
✓
Answer
Correct option: A.
${(C{H_3})_4}{N^ + }{I^ - }$
a
The reaction is expected to be most spontaneous when there is leaving the group.
The reaction is expected to be most spontaneous when there is leaving the group.
The $CH _3$ group with positive $N$ atom is more electron deficient and to more reactive towards the nucleophile.
$\left( CH _3\right)_4 N ^{+} I ^{-}+ OH ^{-} \stackrel{ SN ^2}{\longrightarrow} CH _3 OH$
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