Compound $\ce{C_2H_6O}$ has two isomers $X$ and $Y.$ On reaction with $HI, X$ gives alkyl iodide and water while $Y$ gives alkyl iodide and alcohol.Compounds $X$ and $Y$ are respectively:
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$\ce{(X): C_{2}H_5OH + HI \rightarrow C_2H_{5}I+H_2O(Y):
CH_{3}OCH_3 + HI \rightarrow CH_{3}I+CH_{3}OH}$
CH_{3}OCH_3 + HI \rightarrow CH_{3}I+CH_{3}OH}$
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