Question
Compute: L.C.M. (6!,7!,8!)

Answer

We have, 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 6! = 6 × 5 × 4 × 3 × 2 × 1 and $\therefore$ L.C.M. (6!,7!,8!) = 8!

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