Reduce the given equation into the intercept form and find the in… - Vidyadip

Question

Reduce the given equation into the intercept form and find the intercept on the axis. 3 y + 2 = 0

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Answer

Here 3 y + 2 = 0
$\Rightarrow 3y = - 2$
$ \Rightarrow \frac{{3y}}{{ - 2}} = 1 \Rightarrow \frac{{0x}}{{ - 2}} + \frac{{3y}}{{ - 2}} = 1 \Rightarrow \frac{{0x}}{{ - 2}} + \frac{y}{{\frac{{ - 2}}{3}}} = 1$
which is required intercept form.
Comparing it with $\frac{x}{a} + \frac{y}{b} = 1$ we have
a = 0 and b = -2/3.

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