MCQ
Concentrated ${H_2}S{O_4}$ cannot be used to prepare $HBr$ from $NaBr$, because it
- AReduces $HBr$
- ✓Oxidises $HBr$
- CDisproportionates $HBr$
- DReacts slowly with $NaBr$
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$\ln k=33.24-\frac{2.0 \times 10^{4} \,K }{ T }$
The Activation energy for the reaction is given by $...\,k\,\,J mol ^{-1}$. (In Nearest integer)
(Given: $R =8.3\, J\, K ^{-1} \,mol ^{-1}$ )


