MCQ
Concentrated $HN{O_3}$ reacts with ${I_2}$ to give
- A$HI$
- B$HOI$
- ✓$HOI{O_2}$
- D$HOI{O_3}$
✓
Answer
Correct option: C.
$HOI{O_2}$
c
(c)${I_2} + 10HN{O_3}\, \to \,2HI{O_3} + 10N{O_2} + 4{H_2}O$
(c)${I_2} + 10HN{O_3}\, \to \,2HI{O_3} + 10N{O_2} + 4{H_2}O$
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