- A$[Xe]\,4f^{14}\, 5d^1$
- ✓$[Xe]\,4f^{14}$
- C$[Xe]\,4f^{14}\, 6s^2$
- D$[Xe]\,4f^{14}\,5d^1\,6s^2$
hence $Yb^{+2}$ is $[Xe]\,4f^{14}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A$. $T _4 > T _3 > T _2 > T _1$
$B.$ The black body consists of particles performing simple harmonic motion.
$C.$ The peak of the spectrum shifts to shorter wavelength as temperature increases.
$D.$ $\frac{ T _1}{ v _1}=\frac{ T _2}{ v _2}=\frac{ T _3}{ v _3} \neq$ constant
$E.$ The given spectrum could be explained using quantisation of energy.

Product is


Statement $I$ : The boiling point of three isomeric pentanes follows the order
n-pentane $>$ isopentane $>$ neopentane
Statement $II$ : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below: