MCQ
Conjugate acid of $HPO_4^{-2}$ is
- A$H_3PO_4$
- ✓${H_2}PO_4^\Theta $
- C$PO_4^{ - 3}$
- D${H_2}PO_3^\Theta $
$H _2 PO _4^{-} \rightarrow H ^{+}+ HPO _4^{2-}$
The base and its conjugate acid differ by one proton only.
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Product of the above reaction is
Reason : The only property that determines its aromatic behaviour is its planar structure.