MCQ
If reaction is started with $NH_4COONH_2(s)$ and equilibrium mixture has pressure of $3\, atm$ then $K_P$ for $NH_4COONH_2(s) \rightleftharpoons 2NH_3(g) + CO_2(g)$ is .....$atm^3$
- ✓$4$
- B$27$
- C$\frac{4}{{27}}$
- D$\frac{1}{{27}}$
$P_e$ $:$ $2\,P$ $P$
$=2\times 1$ $=1\,atm$
$=2\,atm$
$\therefore \mathrm{K}_{\mathrm{P}}=\left(\mathrm{P}_{\mathrm{NH}_{3}}\right)^{2} \times \mathrm{P}_{\mathrm{CO}_{2}}=2^{2} \times 1\, \mathrm{atm}^{3}=4\, \mathrm{atm}^{3}$
(given $2 \mathrm{P}+\mathrm{P}=3, \mathrm{P}=1)$
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