Consider a wire having current $10\,A$ having area of crossection $1\,cm^2$. If number of electrons per unit volume is $9 \times 10^{28}\, m^{-3}$. Find the drift velocity of electrons
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The relation between current and drift velocity
I.e1 $= V _{\text {d.ena }}$
where $I$ = current
$V _{ d }=$ current velocity
$e =$ electron
$n =$ no. of electrons per unit volume
$a=$ area of cross section
Now, $V_d=\frac{I}{\text { nea }}$
$=\frac{10}{1 \times 10^{-4} \times 9 \times 10^7 \times 28}=1.94 \times 10^{-3} m / s$
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