In a meter bridge experiment null point is obtained at 20, cm from one end of the wire when resistance X is balanced against another

Q: In a meter bridge experiment null point is obtained at $20\, cm$ from one end of the wire when resistance $X$ is balanced against another resistance $Y$. If $X < Y$, then where will be the new position of the null point from the same end, if one decides to balance a resistance of $4X$ against $Y$ ........... $cm$

a (a) In balancing condition, $\frac{{{R_1}}}{{{R_2}}} = \frac{{{l_1}}}{{{l_2}}} = \frac{{{l_1}}}{{100 - {l_1}}}$ $ \Rightarrow $ $\frac{X}{Y} = \frac{{20}}{{80}} = \frac{1}{4}$.....$(i)$ and $\frac{{4X}}{Y} = \frac{l}{{100 - l}}$.....$(ii)$ $ \Rightarrow $ $\frac{4}{4} = \frac{l}{{100 - l}}$$ \Rightarrow $ $l = 50\,cm$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In a meter bridge experiment null point is obtained at $20\, cm$ from one end of the wire when resistance $X$ is balanced against another resistance $Y$. If $X < Y$, then where will be the new position of the null point from the same end, if one decides to balance a resistance of $4X$ against $Y$ ........... $cm$

A$50$
B$80$
C$40$
D$70$

AIEEE 2004, Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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