Consider a wire having current 10,A having area of crossection 1,cm^2. If number of electrons per unit volume is 9 times 10^{28}, m^{-3}. Find the

Q: Consider a wire having current $10\,A$ having area of crossection $1\,cm^2$. If number of electrons per unit volume is $9 \times 10^{28}\, m^{-3}$. Find the drift velocity of electrons

a The relation between current and drift velocity I.e1 $= V _{\text {d.ena }}$ where $I$ = current $V _{ d }=$ current velocity $e =$ electron $n =$ no. of electrons per unit volume $a=$ area of cross section Now, $V_d=\frac{I}{\text { nea }}$ $=\frac{10}{1 \times 10^{-4} \times 9 \times 10^7 \times 28}=1.94 \times 10^{-3} m / s$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Consider a wire having current $10\,A$ having area of crossection $1\,cm^2$. If number of electrons per unit volume is $9 \times 10^{28}\, m^{-3}$. Find the drift velocity of electrons

A$6.94 \times {10^{ - 6}}\,m/s$
B$1.94 \times {10^{ - 3}}\,m/s$
C$5.94 \times {10^{ - 2}}\,m/s$
D$2.94 \times {10^{ - 4}}\,m/s$

Easy

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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