MCQ
Consider an electron $(m = 9.1 \times {10^{ - 31}}kg)$ confined by electrical forces to move between two rigid walls separated by $1.0 \times {10^{ - 9}}$ metre, which is about five atomic diameters. The quantised energy value for the lowest stationary state is
  • A
    $12 \times {10^{ - 20}}Joule$
  • $6.0 \times {10^{ - 20}}Joule$
  • C
    $6.0 \times {10^{ - 18}}Joule$
  • D
    $6\ Joule$

Answer

Correct option: B.
$6.0 \times {10^{ - 20}}Joule$
b
(b) It will form a stationary wave

$\lambda = 2l = 2 \times {10^{ - 9}}m$

$ \Rightarrow \lambda = \frac{h}{{\sqrt {2mE} }}$

$ \Rightarrow E = \frac{{{h^2}}}{{2m{\lambda ^2}}} = 6 \times {10^{ - 20}}J$

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