MCQ
Consider $Cu ^{2+} \mid Cu$ electrode. What is the electrode potential if $0.01 M Cu ^{2+}$ solution is used?
$
\left(T=298 K, E_{\frac{C u^{2+}}{C u}}^o=0.34 V\right)
$
  • A
    0.399 V
  • B
    0.281 V
  • C
    0.591 V
  • D
    0.222 V

Answer

B. 0.281 V
Explanation:
$\begin{array}{l}E_{\left(\frac{C_u{ }^{2+}}{C_u}\right)}=E_{\left(\frac{C u{ }^{2+}}{C_u}\right)}^o-\frac{0.059}{n} \log \left[\frac{1}{\left[C u^{2+}\right]}\right. \\=0.34-\frac{0.059}{2} \log \frac{1}{0.01} \\=0.3400-0.059=0.281 V\end{array}$

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