Consider the circuit given here with the following parameters $E.M.F.$ of the cell = $12\, V$. Internal resistance of the cell $ = 2\,\Omega $. Resistance $R = 4\,\Omega $ Which one of the following statements in true
ARate of energy loss in the source is $=$ $8\, \Omega$
BRate of energy conversion in the source is $16\, \Omega$
CPower output in is $=$ $8 \,\Omega$
DPotential drop across $R$ is $=$ $16 \,V$
Easy
Download our app for free and get started
ARate of energy loss in the source is $=$ $8\, \Omega$
a (a) $i = \frac{{12}}{{(4 + 2)}} = 2\,A$
Energy loss inside the source $ = {i^2}r$ $ = {(2)^2} \times 2 = 8 \,\Omega$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
In an electrolyte $3.2 \times {10^{18}}$ bivalent positive ions drift to the right per second while $3.6 \times {10^{18}}$ monovalent negative ions drift to the left per second. Then the current is
Two heating coils, one of fine wire and the other of thick wire of the same material and of the same length are connected in series and in parallel. Which of the following statement is correct
Variation of current passing through a conductor as the voltage applied across its ends as varied is shown in the adjoining diagram. If the resistance $(R)$ is determined at the points $A$, $B$, $C$ and $D$, we will find that
In the circuit shown the variable resistance is so adjusted that the ammeter reading is same in both the position $1$ and $2$ of the key. The reading of ammeter is $2A$. If $E = 20V$, then $x$ is :- ................... $\Omega$
In given hollow cylindrical conductor current density is $J = \frac{J_0}{r^2}$ where $J_0$ is constant and $r$ is the distance from axis of cylinder. If radius of inner surface is $'a'$ and radius of outer surface is $2a$ then find current passed through the conductor.
The resistance of a wire is $20\, ohms$. It is so stretched that the length becomes three times, then the new resistance of the wire will be ............. $ohms$