MCQ
Consider the figure provided.

$1 \mathrm{~mol}$ of an ideal gas is kept in a cylinder, fitted with a piston, at the position $\mathrm{A}$, at $18^{\circ} \mathrm{C}$. If the piston is moved to position $B$, keeping the temperature unchanged, then ' $x$ ' $L$ atm work is done in this reversible process.

$\mathrm{x}=$ . . . . . . $\mathrm{L} \mathrm{atm.} \mathrm{(nearest} \mathrm{integer)}$

[Given : Absolute temperature $={ }^{\circ} \mathrm{C}+273.15$, $\left.\mathrm{R}=0.08206 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right]$

  • A
    $50$
  • $55$
  • C
    $60$
  • D
    $65$

Answer

Correct option: B.
$55$
b
$\omega=-\mathrm{nRT} \ln \left(\frac{\mathrm{V}_2}{\mathrm{~V}_1}\right)$

$=-1 \times .08206 \times 291.15 \ln \left(\frac{100}{10}\right)$

$=-55.0128$

Work done by system $\approx 55 \mathrm{~atm}$ lit.

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