Consider the following
$C{H_3} - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(I)}}
$
$
Ph - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(II)}}
$
$
Ph - N{H_2}$
$
\,\,\,\,\,\,\,\,\,{\rm{(III)}}
$
Correct order of their basic strength is
$C{H_3} - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(I)}}
$
$
Ph - C{H_2} - N{H_2}$
$
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{(II)}}
$
$
Ph - N{H_2}$
$
\,\,\,\,\,\,\,\,\,{\rm{(III)}}
$
Correct order of their basic strength is
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Order of basic strength is$\underbrace{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}_{+\,I}$ $>\underbrace{Ph}_{-\,I}-C{{H}_{2}}-N{{H}_{2}}$ $>\,\underset{\begin{smallmatrix}
delocalise \\
l.p.
\end{smallmatrix}}{\mathop{Ph\,-\,\underset{\scriptscriptstyle\centerdot\centerdot}{N}{{H}_{2}}}}\,$
delocalise \\
l.p.
\end{smallmatrix}}{\mathop{Ph\,-\,\underset{\scriptscriptstyle\centerdot\centerdot}{N}{{H}_{2}}}}\,$
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