The compound A with following sequence of reaction gave benzoic acid. Axrightarrow{NaN{{O}_{2}}/HCl}Bxrightarrow{KCN}Cxrightarrow{{{H}_{3}}{{O}^{+}}} benzoic acid The compound A is

Q: The compound $A$ with following sequence of reaction gave benzoic acid. $A\xrightarrow{NaN{{O}_{2}}/HCl}B\xrightarrow{KCN}C\xrightarrow{{{H}_{3}}{{O}^{+}}}$ benzoic acid The compound $ A$ is

b (b) $\underset{\text{Aniline}}{\mathop{\underset{\text{(A)}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,}}\,\underset{{{0}^{o}}C}{\mathop{\xrightarrow{NaN{{O}_{2}}+HCl}}}\,\underset{\text{(B)}}{\mathop{{{C}_{6}}{{H}_{5}}{{N}_{2}}Cl}}\,\xrightarrow{KCN}\underset{\text{(C)}}{\mathop{{{C}_{6}}{{H}_{5}}CN}}\,$ $\xrightarrow{{{H}_{3}}O}$ $\underset{\text{(D)}}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,$

SECTION - A [CHEMISTY - MCQ]

GSEB - English Medium

The compound $A$ with following sequence of reaction gave benzoic acid.

$A\xrightarrow{NaN{{O}_{2}}/HCl}B\xrightarrow{KCN}C\xrightarrow{{{H}_{3}}{{O}^{+}}}$ benzoic acid

The compound $ A$ is

A
Nitrobenzene
B
Aniline
C
Benzaldehyde
D
Amides

Difficult

STD 11 Science
JEE
STD 12 - 9. Amines
Chemistry

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