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5. Co-ordination chemistry — Chemistry STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceChemistry5. Co-ordination chemistry1 Mark
MCQ
Consider the following complex ions  $ \mathrm{P}=\left[\mathrm{FeF}_6\right]^{3-} $  ,  $ \mathrm{Q}=\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+} $  ,  $ \mathrm{R}=\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$  The correct order of the complex ions, according to their spin only magnetic moment values (in $B.M.$) is :
  • A
    $ R < Q <  P$
  • B
     $R < P < Q$
  • ✓
     $Q < R < P$
  • D
    $ Q < P < R$
✓

Answer

Correct option: C.
 $Q < R < P$
c
$\left[\mathrm{FeF}_6\right]^{3-}: \mathrm{Fe}^{+3}:[\mathrm{Ar}] 3 \mathrm{~d}^5$

$IMAGE$

F : Weak field Ligand No. of unpaired electron'$s=5$

$ \mu=\sqrt{5(5+2)} $

$ \mu=\sqrt{35} \mathrm{BM} $

$ {\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+2}: \mathrm{V}^{+2}: 3 \mathrm{~d}^3}$

$IMAGE$

No. of unpaired electron's $=3$

$ \mu=\sqrt{3(3+2)} $

$ \mu=\sqrt{15} \mathrm{BM} $

$ {\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+2}: \mathrm{Fe}^{+2}: 3 \mathrm{~d}^6}$

$\mathrm{H}_2 \mathrm{O}$ : Weak field Ligand

$IMAGE$

No. of unpaired electron's$=4$

$ \mu=\sqrt{4(4+2)} $

$ \mu=\sqrt{24} \mathrm{BM}$

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