MCQ
Consider the following circuit given below. The bulb will light up, if
  • A
    $S_1, S_2$ and $S_3$ are all closed
  • B
    $S_1$ is closed but $S_2$ and $S_3$ are open
  • $S_2$ and $S_3$ are closed but $S_1$ is open
  • D
    $S_1$ and $S_3$ are closed but $S_2$ is open

Answer

Correct option: C.
$S_2$ and $S_3$ are closed but $S_1$ is open
c
(c)

In given circuit, when $S_1$ and $S_3$ both are closed, then source is short circuited. Closing either $S_1$ or $S_3$ does not completes any of path. Hence, they produce no change in circuit.

On closing $S_2$ alone the circuit containing bulb is complete. Hence, bulb will light up when $S_2$ is closed alongwith $S_3$ but $S_1$ is open. Option $(c)$ is correct.

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