MCQ
Consider the following ${E^0}$values :

${E^0}_{F{e^{3 + }}/F{e^{2 + }}}$ $=$ $ + 0.77\;V$

${E^0}_{S{n^{2 + }}/Sn} = - 0.14\;V$ Under standard conditions the potential for the reaction $S{n_{(s)}} + 2F{e^{3 + }}(aq) \to 2F{e^{2 + }}(sq) + S{n^{2 + }}(aq)$ is ............ $\mathrm{V}$

  • $0.91$
  • B
    $1.40$
  • C
    $1.68$
  • D
    $0.63$

Answer

Correct option: A.
$0.91$
a
(a)For $S{n_{(s)}} + 2Fe_{(aq)}^{3 + } \to 2Fe_{(aq)}^{2 + } + Sn_{(aq)}^{2 + }$

$E_{Cell}^0 = E_{Sn/S{n^{2 + }}}^0 + E_{F{e^{3 + }}/F{e^{2 + }}}^0$ $ = (0.14) + (0.77)$

$E_{Cell}^{} = 0.91\;Volts$.

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