MCQ
Consider the following ionisation reactions

$I.E.\, (kJ \,mol^{-1})$ $I.E.\, (kJ\, mol^{-1})$
$A_{(g)} \to A^+_{(g)}+e^-,$     $A_1$ $B_{(g)} \to B^{+}_{(g)}+e^-,$     $B_1$
$B^+_{(g)} \to B^{2+}_{(g)}+e^-,$     $B_2$ $C_{(g)} \to C^{+}_{(g)}+e^-,$     $C_1$
$C^+_{(g)} \to C^{2+}_{(g)}+e^-,$     $C_2$ $C^{2+}_{(g)} \to C^{3+}_{(g)}+e^-,$     $C_3$

If monovalent positive ion of $A,$ divalent positive ion of $B$ and trivalent  positive ion of $C$ have zero electron. Then incorrect order of corresponding  $I.E.$ is

  • A
    $C_3 > B_2 > A_1$
  • B
    $B_1 > A_1 > C_1$
  • C
    $C_3 > C_2 > B_2$
  • $B_2 > C_3 > A_1$

Answer

Correct option: D.
$B_2 > C_3 > A_1$
d
$(d)\,\, A \Rightarrow H(1s^1)$

$B \Rightarrow He(1s^2)$

$C \Rightarrow Li (1s^2\,2s^1)$

$A_1 = IE_1(A)$           $B_2 = IE_2(B)$

$B_1 = IE_1(B)$           $C_2 = IE_2(C)$

$C_1 = IE_1(C)$           $C_3 = IE_3(C)$

$B_1 > A_1 > C_1$       $C_3 > B_2 > A_1$          $C_3 > C_2 > B_2$

$He > H > Li$                 $Li^{2+} \,He^+\,H$         $Ll^{2+} Li^+He^+$

$1s^2\,1s^1 \,2s^1$            $1s^1\,1s^1\,1s^1$              $1s^2\,1s^2\,1s^1$

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