MCQ
Consider the following reaction
(image) $\frac{{{H_2}}}{{pd - BaS{O_4}}}\,'A'$
The product $'A'$ is
- A$C_6H_5COCH_3$
- B$C_6H_5Cl$
- ✓$C_6H_5CHO$
- D$C_6H_5OH$
✓
Answer
Correct option: C.
$C_6H_5CHO$
c
It is rosenmund's reaction, which is used in partial reduction of acidchlorides into aldehydes
It is rosenmund's reaction, which is used in partial reduction of acidchlorides into aldehydes
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\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,|| \\
H-O-C-C- \\
\end{matrix}\begin{matrix}
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||\,\,\, \\
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\end{matrix} \\
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\end{align}$
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