MCQ
Consider the function $\mathrm{f}:(0,2) \rightarrow \mathrm{R}$ defined by $f(x)=\frac{x}{2}+\frac{2}{x}$ and the function$ g(x)$ defined by $g(x)=\left\{\begin{array}{cc}\min \{f(t)\}, & 0 < t \leq x \text { and } 0 < x \leq 1 \\ \frac{3}{2}+x, & 1 < x< 2\end{array}\right.$. Then
  •  $g$ is continuous but not differentiable at $x=1$
  • B
    $\mathrm{g}$ is not continuous for all $\mathrm{x} \in(0,2)$
  • C
     $g$ is neither continuous nor differentiable at $x=1$
  • D
     $g$ is contimuous and differentiable for all $\mathrm{x} \in(0,2)$

Answer

Correct option: A.
 $g$ is continuous but not differentiable at $x=1$
a
$ f:(0,2) \rightarrow R ; f(x)=\frac{x}{2}+\frac{2}{x} $

$ f^{\prime}(x)=\frac{1}{2}-\frac{2}{x^2}$

$\therefore \mathrm{f}(\mathrm{x})$ is decreasing in domain.

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