Question
Consider the objective function Z = 40x + 50y The minimum number of constraints that are required to maximize Z are:
  1. 4
  2. 2
  3. 3
  4. 1

Answer

  1. 3

Solution:

Since in the given function Z = 40x + 50y, two variables are used.

So, the two constraints will be $\text{x}\geq0,\text{y}\geq0$ and the third one will be of the type

$\text{ax}+\text{by}\geq\text{c}.$

Hence, at least 3 constraints are required.

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