Question
Consider the situation described in the previous problem. Suppose the current i enters the loop at the point A and leaves it at the point B. Find the magnetic field at the centre of the loop.
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Answer
$\overrightarrow{\text{B}}$ due t BC$\overrightarrow{\text{B}}$ due to AD at Pt ‘P’ are equal ore Opposite
Hence net $\overrightarrow{\text{B}}=0$
Similarly, due to AB & CD at P = 0 \
$\therefore$ The net B r at the Centre of the square loop = zero
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