MCQ
Consider two rods of same length and different specific heats $\left( c _1, c _2\right)$, thermal conductivities $\left( K _1, K_2\right)$ and area of cross-sections $\left(A_1, A_2\right)$ and both having temperatures $\left(T_1, T_2\right)$ at their ends. If their rate of loss of heat due to conduction is equal, then:
- A$\frac{K_2 A_1}{c_2}=\frac{K_1 A_2}{c_1}$
- B$K _1 A_1= K _2 A_2$
- C$K _2 A_1= K _1 A_2$
- D$\frac{K_1 A_1}{c_1}=\frac{K_2 A_2}{c_2}$
