MCQ
Considering the state of hybridization of carbon atoms, find out the molecule among the following which is linear ?
- A$CH_3 - CH=CH - CH_3$
- ✓$CH_3 - C\equiv C - CH_3$
- C$CH_2\equiv CH - CH_2 - C \equiv CH$
- D$CH_3 - CH_2 - CH_2 - CH_3$
✓
Answer
Correct option: B.
$CH_3 - C\equiv C - CH_3$
b
In case of $\mathrm{sp}^{3}$ hybridised carbon bond angle is $109^{\circ} 28^{\prime} ; \mathrm{sp}^{2} ; \mathrm{sp}^{2} ;$ hybridised carbon, bond angle is $120^{\circ}$ and $sp$ hybridised carbon, bond angle is $180^{\circ}$
In case of $\mathrm{sp}^{3}$ hybridised carbon bond angle is $109^{\circ} 28^{\prime} ; \mathrm{sp}^{2} ; \mathrm{sp}^{2} ;$ hybridised carbon, bond angle is $120^{\circ}$ and $sp$ hybridised carbon, bond angle is $180^{\circ}$
So, only
$\mathrm{CH}_{3}-\underset{\mathrm{sp}}{\mathrm{C}} \equiv \underset{\mathrm{sp}}{\mathrm{C}}-\mathrm{CH}_{3}$ is linear.
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