Download App

1. Some basic concept of chemistry — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry1. Some basic concept of chemistry1 Mark
MCQ
One sample of atmospheric air is found to have $0.03\%$ of carbon dioxide and another sample $0.04\%$. This is evidence that
  • A
    The law of constant composition is not always true
  • B
    The law of multiple proportions is true
  • C
    Air is a compound
  • ✓
    Air is a mixture
✓

Answer

Correct option: D.
Air is a mixture
d
Yes, this illustrates that air is a mixture because air is a composition of many types of gas.

A mixture contains a combination of several elements or compounds. For a mixture, the ratio of constituent elements or compounds is not fixed and it can vary.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 1. Some basic concept of chemistry→1. Some basic concept of chemistry — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

End product of the reaction is
→
Which carbonyl compound has maximum dipole moment
→
The relation between atomic number $(Z)$ and atomic mass $(A)$ for light elements is given by :
→
Which one has maximum oxidation number of phosphorous
→
The enthalpies of all elements in their standard states are :
→
An organic compound with $C = 40\%$ and $H = 6.7\%$ will have the empirical formula
→
The solubility product of a sparingly soluble salt $AB$ at room temperature is $1.21 \times 10^{-6},$ its molar solubility is :
→
On a thin layer chromatographic plate, an organic compound moved by $3.5 \mathrm{~cm}$, while the solvent moved by $5 \mathrm{~cm}$. The retardation factor of the organic compound is____ $\times 10^{-1}$
→
Which of the following overlapping is not present in $XeO_3$ molecule ?
→
The low solubility of $\ce{LiF}$ and $\ce{Css}$ is due to:
→