Question
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°

Answer

Steps of Construction :
(i) Draw a line segment $A B=6.5 cm$

(ii) At A, draw a ray making an angle of $45^{\circ}$ and cut off $AC =5.8 cm$
(iii) Join CB.
$\triangle ABC$ is the required triangle.

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