Question
Construct a ∆ ABC such that:
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
✓
Answer
Steps of Construction :
(i) Draw a line segment $BC =6 cm$.
(ii) At $C$, draw a ray making an angle of $75^{\circ}$ and cut off $C A=5.7 cm$.
(iii) join $A B$.
$\triangle A B C$ is the required triangle.
(i) Draw a line segment $BC =6 cm$.
(ii) At $C$, draw a ray making an angle of $75^{\circ}$ and cut off $C A=5.7 cm$.
(iii) join $A B$.
$\triangle A B C$ is the required triangle.
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