Question
Construct a parallelogram $PQRS$ in which $QR = 6\ cm, PQ = 4\ cm$ and $\angle\text{PQR}=60^\circ.$
✓
Answer
Steps of construction:
Step 1: Draw $PQ = 4cm.$
Step 2: Make $\angle\text{PQR}=60^\circ.$
Step 2: With $Q$ as the centre, draw an arc of $6cm$ and name that point as $R.$
Step 3: With $R$ as the centre, draw an arc of $4cm$ and name that point as $S.$
Step 4: Join $SR$ and $PS.$
Then, $PQRS$ is the required parallelogram.
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