Question
Construct a quadrilateral $ABCD$ in which $AB = 7.7\ cm, BC = 6.8\ cm, CD = 5.1\ cm, AD = 3.6\ cm$ and $\angle\text{C}=120^\circ.$
✓
Answer
Steps of construction:
Step $I$: Draw $DC = 5.1\ cm$.
Step $II$: Construct $\angle\text{DCB}=120^\circ.$
Step $III$: With $C$ as the centre and radius $6.8\ cm$, cut off $BC = 6.8\ cm$.
Step $IV$: With $B$ as the centre and radius $7.7\ cm$, draw an arc.
Step $V$: With $D$ as the centre and radius $3.6\ cm$, draw an arc to intersect the arc drawn in Step $IV$ at $A$.
Step $VI$: Join $AB$ and $AD$ to obtained the required quadrilateral.
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