Question
Construct a quadrilateral ABCD, in which AB = BC = 3 cm, AD = 5 cm, $\angle\text{A}=90^\circ$ and $\angle\text{B}=105^\circ.$

Answer


Steps of construction:
Step I: Draw AB = 3cm.
Step II: Construct $\angle\text{DAB}=90^\circ$ at A.
Step III: With A as the centre and radius 5cm, cut off AD = 5cm.
Step IV: Construct $\angle\text{ABC}=105^\circ$ at B.
Step V: With B as the centre and radius 3cm, cut off BC = 3cm.
Step VI: Join CD.
The quadrilateral so obtained is the required quadrilateral.

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