Question
Construct a rectangle $\text{ABCD}$, when $AD = 3.2\ cm$ and diagonal $BD = 5.5\ cm$. Measure $CD.$
✓
Answer
Steps of construction:
$1$. Draw $AD =3.2 \ cm$
$2$. Draw $\angle X A D=90^{\circ}$.
$3.$ With $D$ as centre and radius $BD =5.5 \ cm$, draw an arc to cut $AX$ at point $B$.
$4$. Join $BD.$
$5$. With $B$ as centre and radius $3.2 \ cm$ draw an arc and with $D$ as centre and radius $=A B$, draw another arc to cut the previous arc at $C$.
$6$. Join $B C$ and $C D$.
Thus, $\text{ABCD}$ is the required rectangle.
$C D=4.5 \ cm$
$1$. Draw $AD =3.2 \ cm$
$2$. Draw $\angle X A D=90^{\circ}$.
$3.$ With $D$ as centre and radius $BD =5.5 \ cm$, draw an arc to cut $AX$ at point $B$.
$4$. Join $BD.$
$5$. With $B$ as centre and radius $3.2 \ cm$ draw an arc and with $D$ as centre and radius $=A B$, draw another arc to cut the previous arc at $C$.
$6$. Join $B C$ and $C D$.
Thus, $\text{ABCD}$ is the required rectangle.
$C D=4.5 \ cm$
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