Question
Construct a rectangle $\text{PQRS}$, when its Area $=33.8 \ cm^2$ and breadth $=6.5 \ cm$
✓
Answer
Since area of rectangle $=33.8 \ cm^2$
And, breadth $=6.5 \ cm$
Length $=$ Area $\div$ Breadth $=33.8 \div 6.5=5.2 \ cm$
Steps of construction:
$1$. Draw $B C=6.5 \ cm$
$2$. Through $B$, draw $B P$ such that $\angle B=90^{\circ}$
$3$. From $B P$, cut $B A=5.2 \ cm$
$4$. With $A$ and $C$ as centres and radii $6.5 \ cm$ and $5.2 \ cm$ respectively, draw arcs cutting each other at $D$.
$5$. Join $A D$ and $C D$.
Thus, $\text{ABCD}$ is the required triangle
.
And, breadth $=6.5 \ cm$
Length $=$ Area $\div$ Breadth $=33.8 \div 6.5=5.2 \ cm$
Steps of construction:
$1$. Draw $B C=6.5 \ cm$
$2$. Through $B$, draw $B P$ such that $\angle B=90^{\circ}$
$3$. From $B P$, cut $B A=5.2 \ cm$
$4$. With $A$ and $C$ as centres and radii $6.5 \ cm$ and $5.2 \ cm$ respectively, draw arcs cutting each other at $D$.
$5$. Join $A D$ and $C D$.
Thus, $\text{ABCD}$ is the required triangle
.
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