Question
Construct a rhombus whose diagonals $AC = 7.4\ cm$ and $BD = 6\ cm.$
✓
Answer
The diagonals of a rhombus bisect each other.
Steps of Construction:
$1$) Draw $AC =7.4 \ cm$
$2$) Draw perpendicular bisector to $A C$ which cuts $A C$ at $O$.
$3)$ From this perpendicular cut $O D$ and $O B$ such that
$OD = OB =\frac{1}{2} BD =\frac{1}{2} \times 6 \ cm =3 \ cm$
$4)$ Join $A B, B C, C D$ and $A D$
$5)$
$\text{ABCD}$ is the required rhombus.
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