Question
Construct a rhombus whose side $AB = 5\ cm$ and diagonal $AC = 6\ cm$. $ME$ asure $DB$ and $AD.$
✓
Answer
In rhombus all sides are equal.
$1)$ Draw $AC = 6\ cm.$
$2)$ With $A$ as centre and radius $5\ cm$, draw two arcs one above $ac$ and the other below $AC.$
$3)$ With $C$ as centre and radius $5\ cm$ draw two acrs one above $AC$ and the other below $AC$ intersecting the arcs of Steps $2$ in $B$ and $D$ respectively.
$4)$ Join $AB, BC, CD$ and $AD.$
$5) \text{ABCD}$ is the required rhombus.
$6)$ On measuring, $AD = 5\ cm$ and $DB = 8\ cm.$
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→ Q.1.Which of the following pair of linear equations represent the given situation?
(a) x + y = 19, 2x + y = 13 (b) x + y = 13, 2x + y = 19
(c) x - y = 19, 2x - y = 13 (d) x + y = 13, 2x - y = 19
Q.2. The perimeter of the outer boundary of the layout is:
(a) 54 m (b) 27 m (c) 50 m (d) 52 m
Q.3. Total area of bedroom 1 and kitchen is:
(a) $60 m^2$ (b) $70 m^2$ (c) $65 m^2$ (d) $95 m^2$
Q.4. The area of the living room is:
(a) $50 m^2$ (b) $60 m^2$ (c) $70 m^2$ (d) $75 m^2$
Q.5. The cost of laying tiles on the floor of the kitchen at the rate of ₹200 per sq mis:
(a) ₹7000 (b) ₹6000 (c) ₹5200 (d) ₹5000
Simplify the following :$\frac{3 \sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4 \sqrt{3}}{\sqrt{6}-\sqrt{2}}+\frac{2 \sqrt{3}}{\sqrt{6}+2}$
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