Question
Construct a rhombus whose side is $5\ cm$ and one angle is of $60^\circ $.
✓
Answer
$\angle\text{B}=60^\circ$
$\angle\text{A}+\angle\text{B}=180^\circ [$sum of co$-$interior angles$]$
$\angle\text{A}=60^\circ=180^\circ$
$\angle\text{A}=120^\circ$
$\text{AB = BC = CD = DA} = 5\ cm$
Steps of Construction:
$1.$ Draw $\text{AB} = 5\ cm$
$2.$ Draw a ray $\text{AY}$ such that $\angle\text{BAY}=120^\circ$
$3.$ Mark a point $D$ such that $\text{AD} = 5\ cm$
$4.$ Draw a ray $\text{BX}$ such that $\angle\text{ABX}=60^\circ$
$5.$ Mark a point $C$ such that $\text{BC} = 5\ cm$
$6.$ Join $C$ and $D$.
Hence, $\text{ABCD}$ is the required rhombus.
$\angle\text{A}+\angle\text{B}=180^\circ [$sum of co$-$interior angles$]$
$\angle\text{A}=60^\circ=180^\circ$
$\angle\text{A}=120^\circ$
$\text{AB = BC = CD = DA} = 5\ cm$
Steps of Construction:
$1.$ Draw $\text{AB} = 5\ cm$
$2.$ Draw a ray $\text{AY}$ such that $\angle\text{BAY}=120^\circ$
$3.$ Mark a point $D$ such that $\text{AD} = 5\ cm$
$4.$ Draw a ray $\text{BX}$ such that $\angle\text{ABX}=60^\circ$
$5.$ Mark a point $C$ such that $\text{BC} = 5\ cm$
$6.$ Join $C$ and $D$.
Hence, $\text{ABCD}$ is the required rhombus.
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