Question
Construct a square of side $4\ cm$.
✓
Answer
All sides of a square are equal $\&$ each side is perpendicular to adjacent side.
So, $\text{AB = BC = CD = DA} = 4\ cm$
Steps of Construction:
$1.$ Draw $\text{AB} = 3\ cm$
$2.$ At $B$ draw $\text{BX}$ such that $\angle\text{ABX}=90^\circ$
$3.$ From $\text{BX}$, cut off $\text{BC} = 4\ cm$
$4.$ With $C$ as centre $\&$ radius $= 4\ cm$, draw an arc
$5.$ With $A$ as centre $\&$ radius $= 4\ cm$, draw another arc to intersect the previous arc at $D$.
$6.$ Join $\text{CD}$ and $\text{AD}$.
Hence, $\text{ABCD}$ is the required square.
So, $\text{AB = BC = CD = DA} = 4\ cm$
Steps of Construction:
$1.$ Draw $\text{AB} = 3\ cm$
$2.$ At $B$ draw $\text{BX}$ such that $\angle\text{ABX}=90^\circ$
$3.$ From $\text{BX}$, cut off $\text{BC} = 4\ cm$
$4.$ With $C$ as centre $\&$ radius $= 4\ cm$, draw an arc
$5.$ With $A$ as centre $\&$ radius $= 4\ cm$, draw another arc to intersect the previous arc at $D$.
$6.$ Join $\text{CD}$ and $\text{AD}$.
Hence, $\text{ABCD}$ is the required square.
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