Question
Construct a square ABCD, when: Perimeter $= 24 \ cm.$
✓
Answer
The perimeter of a square
$P=4 a$
Where $a$ is the length of each side
We have Perimeter $=24 \ cm$
Therefore,
$24=4 a$
$ 4=6$
Therefore the sides of the squares are of length $6 \ cm$.
Steps:
$1$. Draw a line segment $A b=6 \ cm$.
$2$. Draw $A P \perp A B$.
$3$. From $A P$ cut off $A D=6 \ cm$.
$4$. With $B$ as a center and radius, $6 \ cm$ draw an arc.
$5$. With $D$ as center and radius, $6 \ cm$ draw another arc cutting the former arc at $C$.
$6$. Join $B C$ and $C D$.
$\text{ABCD}$ is the required square.
$P=4 a$
Where $a$ is the length of each side
We have Perimeter $=24 \ cm$
Therefore,
$24=4 a$
$ 4=6$
Therefore the sides of the squares are of length $6 \ cm$.
Steps:
$1$. Draw a line segment $A b=6 \ cm$.
$2$. Draw $A P \perp A B$.
$3$. From $A P$ cut off $A D=6 \ cm$.
$4$. With $B$ as a center and radius, $6 \ cm$ draw an arc.
$5$. With $D$ as center and radius, $6 \ cm$ draw another arc cutting the former arc at $C$.
$6$. Join $B C$ and $C D$.
$\text{ABCD}$ is the required square.
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