Question
Construct a square, each of whose diagonals measures $5.8\ cm.$
✓
Answer
We know that the diagonals of a square bisect each other at right angles.
Steps of construction:
Step 1: Draw $AC = 5.8\ cm.$
Step 2: Draw the perpendicular bisector $XY$ of $AC,$ meeting it at $O.$
Step 3: From $O: \text{OB}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$
$\text{OD}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$
Step 4: Join $AB, BC, CD$ and $DA.$
$ABCD$ is the required square.
Steps of construction:
Step 1: Draw $AC = 5.8\ cm.$
Step 2: Draw the perpendicular bisector $XY$ of $AC,$ meeting it at $O.$
Step 3: From $O: \text{OB}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$
$\text{OD}=\frac{1}{2}(5.8)\text{cm}=2.9\text{cm}$
Step 4: Join $AB, BC, CD$ and $DA.$
$ABCD$ is the required square.
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