Question
Find (x + y) ÷ (x − y), if
$\text{x}=\frac{5}{4},\text{y}=\frac{-1}{3}$
$\text{x}=\frac{5}{4},\text{y}=\frac{-1}{3}$
✓
Answer
$\text{x}=\frac{5}{4},\text{y}=\frac{-1}{3}$
$\therefore\text{x}+\text{y}=\frac{5}{4}+\frac{-1}{3}$
$=\frac{15-4}{12}=\frac{11}{12}$
$\text{x}-\text{y}=\frac{5}{4}-\frac{-1}{3}$
$=\frac{15+4}{12}=\frac{19}{12}$
$\therefore (\text{x}+\text{y})\div(\text{x}-\text{y})=\frac{11}{12}\div\frac{19}{12}$
$=\frac{11}{12}\times\frac{12}{19}=\frac{11}{19}$
$\therefore\text{x}+\text{y}=\frac{5}{4}+\frac{-1}{3}$
$=\frac{15-4}{12}=\frac{11}{12}$
$\text{x}-\text{y}=\frac{5}{4}-\frac{-1}{3}$
$=\frac{15+4}{12}=\frac{19}{12}$
$\therefore (\text{x}+\text{y})\div(\text{x}-\text{y})=\frac{11}{12}\div\frac{19}{12}$
$=\frac{11}{12}\times\frac{12}{19}=\frac{11}{19}$
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