Question
Construct a trapezium $\text{ABCD}$ in which $AB = 4.6\ cm, BC = 6.4\ cm, CD = 5.6\ cm, \angle B = 60^\circ $ and $AD \| BC.$
✓
Answer
$AB = 4.6\ cm, BC = 6.4\ cm, CD = 5.6\ cm, \angle B = 60^\circ $ and $AD || BC.$
Steps of construction:
$1)$ Draw $BC = 6.4\ cm$
$2)$ With $B$ as centre, draw an angle of $60^\circ $ and cut an arc with radius $4.6\ cm.$
$3)$ From point $A$, draw a line segment parallel to $BC.$
$4)$ With $C$ as centre and radius $5.6\ cm$ cut an arc on the line segment parallel to $BC$.
Mark the point as $D.$
$5)$ Join $CD.$
$6)\text{ABCD}$ is the required trapezium.
Steps of construction:
$1)$ Draw $BC = 6.4\ cm$
$2)$ With $B$ as centre, draw an angle of $60^\circ $ and cut an arc with radius $4.6\ cm.$
$3)$ From point $A$, draw a line segment parallel to $BC.$
$4)$ With $C$ as centre and radius $5.6\ cm$ cut an arc on the line segment parallel to $BC$.
Mark the point as $D.$
$5)$ Join $CD.$
$6)\text{ABCD}$ is the required trapezium.
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